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36x^2+10=46
We move all terms to the left:
36x^2+10-(46)=0
We add all the numbers together, and all the variables
36x^2-36=0
a = 36; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·36·(-36)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*36}=\frac{-72}{72} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*36}=\frac{72}{72} =1 $
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